1/sinA = sin A
sin^2 A = 1
only when sin A = 1 or -1
That is when A = 90 or 270 degrees
Without aid of tables/caulculator, find all values of A between 0 degrres and 360 degrees.
cosec A= sec A
How you do this question?
4 answers
sec A is cos A
oops 1 over cos A
Sorry, misread question
1/sin A = 1/cos A
sin A = cos A
45 degrees from x axis in all quadrants the sin and cos have the same magnitude but for this they must also have the same sign. That is in quadrants 1 and 3
45 degrees
180+45 = 225 degrees
1/sin A = 1/cos A
sin A = cos A
45 degrees from x axis in all quadrants the sin and cos have the same magnitude but for this they must also have the same sign. That is in quadrants 1 and 3
45 degrees
180+45 = 225 degrees