It falls with zero initial velocity from the roof to the ground which is 12 meters high the way I read it.
v = sqrt (2 * 9.8 * 12)
With what minimum speed must you toss a 130 g ball straight up to hit the 12 m-high roof of the gymnasium if you release the ball 1.3 m above the ground?
I already figured out the minimum speed, 14m/s I'm confused on the next part
With what speed does the ball hit the ground?
Do I use, for values of H, 10.7m or 12m or 13.3m?
3 answers
How did you calculate the minimum speed?
Kf+Uf=Ki+Ui
.5*m*v^2 + 0=.5*m*(vi)^2 + m*9.8*1.3meter
m=mass
v= velo u want to solve for
vi= your initial velo, for you 14m/s
my values where .16kg ball, 13m ceiling, 1.7 off the ground. answer one for me was 14.88, answer 2 was 15.96m/s
.5*m*v^2 + 0=.5*m*(vi)^2 + m*9.8*1.3meter
m=mass
v= velo u want to solve for
vi= your initial velo, for you 14m/s
my values where .16kg ball, 13m ceiling, 1.7 off the ground. answer one for me was 14.88, answer 2 was 15.96m/s