consider the height of the ball.
y = v sinθ t - 16.1t^2
what is v? no idea, but we do know that with a constant horizontal speed of v cosθ, it flew 196 feet. so,
t = 196/(v cosθ)
Plug that in, and you just have to solve
y = 196 tan30.3° - 16.1t^2 = 10.1
While watching a softball game you see a play that makes you wonder how fast a fielder can react to a hit, run to the fence, and leap up to make the catch. In this play, the batter hits a ball when it is barely off the ground. It looks like it will be a home run over the left field wall which is 196 ft. from home plate. As soon as the ball is hit, the left fielder runs to the wall, leaps high, and catches it just before it clears the top of the 10.1 ft. high wall. You estimate that the ball left the bat at an angle of 30.3°. How long after the ball is hit does the fielder have to make the play? (g=32.2 ft/sec2)
1 answer