Question

while on the moon, the Apollo astronauts enjoyed the effect of a gravity much smaller than that on earth. if Neil Armstrong jumped up on the moon with an initial speed of 1.51 m/s to a height of 0.700m, what amount of gravitational acceleration did he experience?

Answer 1

Using conservation of energy,
(1/2)M Vo^2 = M g'H, so
g' = Vo^2/(2H)
is the value of the acceleration of gravity on the moon.

I get 1.63 m/s^2

Answer 2

2gh=v^2
2*0.7*g=1.51^2
1.4g=1.51^2 /g
1.4=2.2801g
g=1.4/2.2801
g=0.6140081575 m/s^2

1.63m/s^2 is not the correct answer, take for example this:

10=5g What is 'g'?
g=10/5=2

Answer 3

1.63 m/s^2 is the correct answer

Answer 4

Marko 1.51^2 /g doesn't equal 2.2801g it equals 2.2801/g. So your answer is the reciprical of the right answer. Nice try though.

Answer 5

While on the moon, the Apollo astronauts enjoyed the effects of a small gravity. If Neil Armstrong jumped up on the moon with an initial speed of 5 m/s to a height of 5.0 m, what amount of gravitational acceleration did he experience? (m/s^2)