Which term of the progression 19+ 18 1/5 + 17 2/5 + …is the first negative term? What is the smallest number of terms which must be taken for their sum to be negative ? Calculate this sum exactly.

Answer 1

Arithmetic series with
a = 19
d = -4/5

a + (n-1)d < 0
19 + (n-1)(-4/5) < 0
19 - (4/5)n + 4/5 < 0
times 5
95 - 4n + 4 < 0
-4n < -99
n > 99/4
n > 24.75
so it must be term(25) which is the first one negative.

check:
term(25) = 19 + 24(-4/5) = -1/5
term(24) = 19 + 23(-4/5) = 3/5
OK

use the formula for sum(n) < 0
to do the 2nd part of your problem

Answer 2

which term of the progression 19+181/5+17 2/5+...is the first negative lterm?which is the smallest number of terrms which must be taken for their sum to be negative?Calculate this sum exactly.

Answer 3

Please give the second part of question with complete solution

Answer 4

Solve the second part

Answer 5

FIND CONSECUTIVE COUNTING NUMBERS WHOSE SUM IS 50.

FIND THE SUM.
19+ 18
how u do this help

Answer 6

thank you

Answer 7

thanks now i know how to solve this