Which of the following statements is true?(1 point)

Responses

2/5⋅11/3<2/5
Start Fraction 2 over 5 End Fraction times Start Fraction 11 over 3 End Fraction less than Start Fraction 2 over 5 End Fraction

11/3⋅2/3>11/3
Start Fraction 11 over 3 End Fraction times Start Fraction 2 over 3 End Fraction greater than Start Fraction 11 over 3 End Fraction

7/3⋅1/3>7/3
Start Fraction 7 over 3 End Fraction times Start Fraction 1 over 3 End Fraction greater than Start Fraction 7 over 3 End Fraction

7/3⋅1/3<7/3

1 answer

To evaluate each statement, we can simplify the expressions and compare the results.

  1. \( \frac{2}{5} \cdot \frac{11}{3} < \frac{2}{5} \):

    • Calculate \( \frac{2}{5} \cdot \frac{11}{3} = \frac{2 \cdot 11}{5 \cdot 3} = \frac{22}{15} \).
    • Compare \( \frac{22}{15} \) with \( \frac{2}{5} \).
    • Convert \( \frac{2}{5} \) to a fraction with a denominator of 15: \( \frac{2}{5} = \frac{6}{15} \).
    • Thus, \( \frac{22}{15} > \frac{6}{15} \). This statement is false.
  2. \( \frac{11}{3} \cdot \frac{2}{3} > \frac{11}{3} \):

    • Calculate \( \frac{11}{3} \cdot \frac{2}{3} = \frac{22}{9} \).
    • Compare \( \frac{22}{9} \) with \( \frac{11}{3} \).
    • Convert \( \frac{11}{3} \) to a fraction with a denominator of 9: \( \frac{11}{3} = \frac{33}{9} \).
    • Thus, \( \frac{22}{9} < \frac{33}{9} \). This statement is false.
  3. \( \frac{7}{3} \cdot \frac{1}{3} > \frac{7}{3} \):

    • Calculate \( \frac{7}{3} \cdot \frac{1}{3} = \frac{7}{9} \).
    • Compare \( \frac{7}{9} \) with \( \frac{7}{3} \).
    • Convert \( \frac{7}{3} \) to a fraction with a denominator of 9: \( \frac{7}{3} = \frac{21}{9} \).
    • Thus, \( \frac{7}{9} < \frac{21}{9} \). This statement is false.
  4. \( \frac{7}{3} \cdot \frac{1}{3} < \frac{7}{3} \):

    • We already calculated \( \frac{7}{3} \cdot \frac{1}{3} = \frac{7}{9} \).
    • Compare \( \frac{7}{9} \) with \( \frac{7}{3} \) (as calculated previously).
    • Thus, \( \frac{7}{9} < \frac{21}{9} \). This statement is true.

Conclusion: The true statement is \( \frac{7}{3} \cdot \frac{1}{3} < \frac{7}{3} \).