Asked by Lucy
Which of the following series is divergent?
a) 1+3(1/4)+9(1/4)^2+27(1/4)^3...
b) 1+3(1/5)+9(1/5)^2+27(1/5)^3...
c) 1+3(1/7)+9(1/7)^2+27(1/7)^3...
d) 1+3(1/2)+9(1/2)^2+27(1/2)^3...
How do you determine if a series in convergent or divergent???
The book that I have is about as clear as mud and I do not understand...
Thanks for your help!!
a) 1+3(1/4)+9(1/4)^2+27(1/4)^3...
b) 1+3(1/5)+9(1/5)^2+27(1/5)^3...
c) 1+3(1/7)+9(1/7)^2+27(1/7)^3...
d) 1+3(1/2)+9(1/2)^2+27(1/2)^3...
How do you determine if a series in convergent or divergent???
The book that I have is about as clear as mud and I do not understand...
Thanks for your help!!
Answers
Answered by
Reiny
This would be a lengthy reply, so see if you can make sense out of this
http://faculty.msmary.edu/heinold/m248spring2007/m248spring2007_convergence_tests.pdf
I will take a look at the first question
1+3(1/4)+9(1/4)^2+27(1/4)^3...
= 1 + 3^1 / 4^1 + 3^2 / 4^2 + ..
= 1 + summation of (3/4)^n as n goes from 1 to infinitity
Now compare this result with what it says about the summation of a geometric series at the top of the link I gave you.
good luck.
http://faculty.msmary.edu/heinold/m248spring2007/m248spring2007_convergence_tests.pdf
I will take a look at the first question
1+3(1/4)+9(1/4)^2+27(1/4)^3...
= 1 + 3^1 / 4^1 + 3^2 / 4^2 + ..
= 1 + summation of (3/4)^n as n goes from 1 to infinitity
Now compare this result with what it says about the summation of a geometric series at the top of the link I gave you.
good luck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.