To demonstrate that polynomials form a closed system under multiplication, we need to show that the product of two polynomials is also a polynomial.
Let's evaluate the given responses:
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Response 1: \((\sqrt{x})(x+1)\)
- This expression includes \(\sqrt{x}\), which is not a polynomial since it is not expressed as a sum of non-negative integer powers of \(x\).
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Response 2: \((x^2 + 1)(x - \frac{1}{2})\)
- Both \(x^2 + 1\) and \(x - \frac{1}{2}\) are polynomials. The product of these two polynomials will also be a polynomial. Therefore, this response demonstrates closure under multiplication.
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Response 3: \(\left(\frac{x^2}{2}\right)\left(\frac{1}{x}\right)\)
- This expression simplifies to \(\frac{x}{2}\), which is indeed a polynomial. However, involving \(\frac{1}{x}\) can cause confusion about closure, as one might argue it's not a polynomial in the standard form due to containing a term with a negative exponent.
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Response 4: \(x^2 + 2x + 1\)
- This is a polynomial, but it does not show multiplication between two polynomials.
The best choice to demonstrate that polynomials form a closed system under multiplication is Response 2: \((x^2 + 1)(x - \frac{1}{2})\), as the product of these polynomials remains a polynomial.