To determine which of the ordered pairs is part of the solution set for the equation \( y = 2x + 5 \), we can substitute the \( x \) values from each pair into the equation and check if the resulting \( y \) value matches the given \( y \) in the ordered pair.
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For (9, 2): \[ y = 2(9) + 5 = 18 + 5 = 23 \quad \text{(Not a solution)} \]
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For (-2, -1): \[ y = 2(-2) + 5 = -4 + 5 = 1 \quad \text{(Not a solution)} \]
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For (-3, -4): \[ y = 2(-3) + 5 = -6 + 5 = -1 \quad \text{(Not a solution)} \]
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For (-3, -1): \[ y = 2(-3) + 5 = -6 + 5 = -1 \quad \text{(This is a solution)} \]
The only ordered pair from the options given that is part of the solution set for the equation \( y = 2x + 5 \) is (-3, -1).