To determine which ordered pair is in the solution set for the equation \( y = 8x - 1 \), we can substitute \( x = 2 \) into the equation and compute \( y \).
Calculating:
\[ y = 8(2) - 1 \] \[ y = 16 - 1 \] \[ y = 15 \]
So when \( x = 2 \), \( y = 15 \).
Now, we can check the ordered pairs:
- For \( (2, 81) \): \( y \neq 15 \)
- For \( (2, 82) \): \( y \neq 15 \)
- For \( (2, 16) \): \( y \neq 15 \)
- For \( (2, 15) \): \( y = 15 \)
Thus, the ordered pair that is in the solution set for \( y = 8x - 1 \) is \( \boxed{(2, 15)} \).