Question

Which of the following ordered pairs is in the solution set for y=8x−1
?(1 point)
Responses

(2,16)
left parenthesis 2 comma 16 right parenthesis

(2,15)
left parenthesis 2 comma 15 right parenthesis

(2,82)
left parenthesis 2 comma 82 right parenthesis

(2,81)

Answer 1

To determine which ordered pair is in the solution set for the equation \( y = 8x - 1 \), we need to substitute \( x = 2 \) into the equation and find the corresponding value of \( y \).

Substituting \( x = 2 \):

\[
y = 8(2) - 1
\]
\[
y = 16 - 1
\]
\[
y = 15
\]

Now we can check which ordered pair matches \( (2, 15) \):

- \( (2, 16) \) giving \( y = 16 \) (not a solution)
- \( (2, 15) \) giving \( y = 15 \) (is a solution)
- \( (2, 82) \) giving \( y = 82 \) (not a solution)
- \( (2, 81) \) giving \( y = 81 \) (not a solution)

Thus, the ordered pair that is in the solution set for \( y = 8x - 1 \) is:

\((2, 15)\)