Which of the following ordered pairs is in the solution set for y=8x−1

Question

?(1 point)
Responses

(2,16)
left parenthesis 2 comma 16 right parenthesis

(2,15)
left parenthesis 2 comma 15 right parenthesis

(2,82)
left parenthesis 2 comma 82 right parenthesis

(2,81)

Answer 1

To determine which of the given ordered pairs is in the solution set for the equation \( y = 8x - 1 \), we can substitute \( x \) from each ordered pair into the equation and see if the resulting value of \( y \) matches the provided \( y \) value.

For \( x = 2 \): \[ y = 8(2) - 1 = 16 - 1 = 15 \]

Now we check each ordered pair:

1. \( (2, 16) \):

   • Calculated \( y = 15 \) (not a solution).

2. \( (2, 15) \):

   • Calculated \( y = 15 \) (this is a solution).

3. \( (2, 82) \):

   • Calculated \( y = 15 \) (not a solution).

4. \( (2, 81) \):

   • Calculated \( y = 15 \) (not a solution).

The only ordered pair that is in the solution set for \( y = 8x - 1 \) is \( (2, 15) \).