Which of the following is a solution of x² + 14x + 112 = 0? If necessary, round to the nearest hundredth.

Answer 1

To find the solution of the given quadratic equation x² + 14x + 112 = 0, we can use the quadratic formula:

x = [-b ± √(b² - 4ac)] / 2a

In this case, a = 1, b = 14, and c = 112. Plugging these values into the formula, we get:

x = [-14 ± √(14² - 4*1*112)] / 2*1
x = [-14 ± √(196 - 448)] / 2
x = [-14 ± √(-252)] / 2
x = [-14 ± √(252)i] / 2
x = [-14 ± 15.87i] / 2

Therefore, the solutions to the equation x² + 14x + 112 = 0 are -7 + 7.94i and -7 - 7.94i.

Answer 2

sorry i meant Which of the following is a solution of x² + 14x + 112 = 0? If necessary, round to the nearest hundredth.
(1 point)
Responses

x = –0.24
x = –0.24
x = –4.24
x = –4.24
4.24
4.24
no solution

Answer 3

To find the solutions of the given quadratic equation x² + 14x + 112 = 0, we can use the quadratic formula:

x = [-b ± √(b² - 4ac)] / 2a

In this case, a = 1, b = 14, and c = 112. Plugging these values into the formula, we get:

x = [-14 ± √(14² - 4*1*112)] / 2*1
x = [-14 ± √(196 - 448)] / 2
x = [-14 ± √(-252)] / 2
x = [-14 ± 15.87i] / 2

Since the discriminant (√(-252)) is negative, there are no real number solutions. Therefore, the correct response is: no solution.