Ask a New Question
Search
Which of the following expressions are identical?
a. (sinx)^-1
b. arcsinx
c. sin x^-1
d. 1/sinx
Ask a New Question
or
answer this question
.
Similar Questions
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
3 answers
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm
(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
3 answers
solve to four decimal places
1.3224sinx + 0.4732=0 :for all real x values solve for sinx, then arcsinx. solve for sinx, then
0 answers
Simplify sin x cos^2x-sinx
Here's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
1 answer
more similar questions