To determine which of the given coordinate pairs is a point on the parabola defined by the equation \( y = -4x^2 - 53x - 56 \), we can substitute the \( x \)-coordinate from each point into the equation and check if we get the corresponding \( y \)-coordinate.
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For the point \((-4, -56)\): \[ y = -4(-4)^2 - 53(-4) - 56 \] \[ = -4(16) + 212 - 56 \] \[ = -64 + 212 - 56 \] \[ = 92 \quad (\text{not } -56) \]
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For the point \((-1, -7)\): \[ y = -4(-1)^2 - 53(-1) - 56 \] \[ = -4(1) + 53 - 56 \] \[ = -4 + 53 - 56 \] \[ = -7 \quad (\text{this is the same as } -7) \]
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For the point \((-4, 220)\): \[ y = -4(-4)^2 - 53(-4) - 56 \] \[ = -4(16) + 212 - 56 \] \[ = -64 + 212 - 56 \] \[ = 92 \quad (\text{not } 220) \]
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For the point \((-1, 13)\): \[ y = -4(-1)^2 - 53(-1) - 56 \] \[ = -4(1) + 53 - 56 \] \[ = -4 + 53 - 56 \] \[ = -7 \quad (\text{not } 13) \]
After checking all the coordinate pairs, we find that the point \((-1, -7)\) is indeed a point on the parabola \( y = -4x^2 - 53x - 56 \).
Thus, the answer is: \(\boxed{(-1, -7)}\)