Which of the following coordination compounds will most likely form a precipitate when treated with an aqueous solution of silver(I) nitrate?
[Cr(NH3)3Cl3]
[Cr(NH3)6]Cl3
[Cr(NH3)Cl]SO4
Na3[Cr(CN)6]
Na3[CrCl6]
1 answer
The idea here is that AgCl is a white insoluble ppt in most solutions. We know that. However, in coordinations complexes, the Cl that is free and clear (from ionic bonding) will be free to form the AgCl. That Cl that is WITHIN the coordination sphere is covalently bound and will not be free to form AgCl. How do you know it is is ionic or covalent? Cl within the brackets are within the coordination sphere. Those Cl outside the brackets probably are ionic and will be free to form AgCl. For example, the first one the Cl is within the brackets so no ppt. Same thing for the last one.
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