Which is the equation of a line that has a slope of 4 and passes through point (1, 6)?

y = 4x – 2
y = 4x + 6
y = 4x + 2
y = 4x – 3

1 answer

To find the equation of the line with a slope of 4 that passes through the point (1, 6), we can use the point-slope form of the equation of a line, which is given by:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line.

Here, \( m = 4 \) and \( (x_1, y_1) = (1, 6) \). Plugging in these values:

\[ y - 6 = 4(x - 1) \]

Now, we simplify the equation:

  1. Distribute the slope on the right: \[ y - 6 = 4x - 4 \]

  2. Add 6 to both sides: \[ y = 4x + 2 \]

Now we can see that the equation of the line is:

\[ y = 4x + 2 \]

Thus, the answer is:

y = 4x + 2