To find the equation of the line with a slope of 4 that passes through the point (1, 6), we can use the point-slope form of the equation of a line, which is given by:
\[ y - y_1 = m(x - x_1) \]
where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line.
Here, \( m = 4 \) and \( (x_1, y_1) = (1, 6) \). Plugging in these values:
\[ y - 6 = 4(x - 1) \]
Now, we simplify the equation:
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Distribute the slope on the right: \[ y - 6 = 4x - 4 \]
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Add 6 to both sides: \[ y = 4x + 2 \]
Now we can see that the equation of the line is:
\[ y = 4x + 2 \]
Thus, the answer is:
y = 4x + 2