Which irrational number is between cubed root of 9 and 25

Answer 1

One possible answer is the irrational number √10.

To see why, first note that the cube root of 9 is approximately 2.08 (since 2^3 = 8 and 3^3 = 27, the cube root of 9 is between 2 and 3). The square of this number is approximately 4.32.

Similarly, 25 is a perfect square (5^2 = 25), so its square root is exactly 5.

Now we can estimate the location of √10 by noting that it's between these two values:

2 < √10 < 5

We could also use a calculator or other methods to get a more precise approximation:

√9 ≈ 3

√10 ≈ 3.16227766...

√25 = 5

So we can see that the irrational number √10 is between the cube root of 9 and 25.