One possible answer is the irrational number √10.
To see why, first note that the cube root of 9 is approximately 2.08 (since 2^3 = 8 and 3^3 = 27, the cube root of 9 is between 2 and 3). The square of this number is approximately 4.32.
Similarly, 25 is a perfect square (5^2 = 25), so its square root is exactly 5.
Now we can estimate the location of √10 by noting that it's between these two values:
2 < √10 < 5
We could also use a calculator or other methods to get a more precise approximation:
√9 ≈ 3
√10 ≈ 3.16227766...
√25 = 5
So we can see that the irrational number √10 is between the cube root of 9 and 25.
Which irrational number is between cubed root of 9 and 25
1 answer