Which irrational number is between cubed root of 9 and 25

1 answer

One possible answer is the irrational number √10.

To see why, first note that the cube root of 9 is approximately 2.08 (since 2^3 = 8 and 3^3 = 27, the cube root of 9 is between 2 and 3). The square of this number is approximately 4.32.

Similarly, 25 is a perfect square (5^2 = 25), so its square root is exactly 5.

Now we can estimate the location of √10 by noting that it's between these two values:

2 < √10 < 5

We could also use a calculator or other methods to get a more precise approximation:

√9 ≈ 3

√10 ≈ 3.16227766...

√25 = 5

So we can see that the irrational number √10 is between the cube root of 9 and 25.
Similar Questions
    1. answers icon 3 answers
  1. Select all possible values for x in the equation.x cubed=375. 5*the cubed root of 3 the cubed root of 375 75*the cubed root of 5
    1. answers icon 5 answers
    1. answers icon 1 answer
  2. Products of Irrational Square Roots Quick Check3 of 53 of 5 Items Question Rewrite the irrational cube root ^3√48 as a product
    1. answers icon 1 answer
more similar questions