Which irrational number is between cubed root of 9 and cubed root of 25

3 answers

The cubed root of 9 is approximately 2.08 and the cubed root of 25 is approximately 2.92.

The irrational number √2 is between 2 and 3.

When we cube √2, we get approximately 2.83, which is between 2.08 and 2.92.

Therefore, √2 is the irrational number that is between the cubed root of 9 and the cubed root of 25.
why are you using square roots, when the question was about cube roots?

Since ∛9 ≈ 2.08 and ∛25 ≈ 2.92, there are infinitely many irrational numbers between ∛9 and ∛25.
You are correct, my apologies for the confusion. Since the question is about cube roots, we can say that there are infinitely many irrational numbers between ∛9 and ∛25. This is because the set of irrational numbers is dense in the real number line, which means that between any two real numbers, there are infinitely many irrational numbers. So, we can conclude that there are infinitely many irrational numbers between ∛9 and ∛25, and we do not need to use square roots for this problem. Thank you for bringing this to my attention.
Similar Questions
  1. Select all possible values for x in the equation.x cubed=375. 5*the cubed root of 3 the cubed root of 375 75*the cubed root of 5
    1. answers icon 5 answers
  2. Simplify the radical 128x4y9−−−−−−−√.(1 point) Responses 14x3y62xy3−−−−√ 14 x cubed y to the 6th power
    1. answers icon 1 answer
  3. limit as h approaches 0cubed root of 8+h -2 divided by h the cubed root sign is under 8+h and not -2 A. 1/12 B.1/4 C.root 2 over
    1. answers icon 2 answers
  4. Convert between the units of volume500mm cubed = cm cubed 16000000cm cubed=m cubed 4000000000m cubed=km cubed 10cm cubed=mm
    1. answers icon 1 answer
more similar questions