The cubed root of 9 is approximately 2.08 and the cubed root of 25 is approximately 2.92.
The irrational number √2 is between 2 and 3.
When we cube √2, we get approximately 2.83, which is between 2.08 and 2.92.
Therefore, √2 is the irrational number that is between the cubed root of 9 and the cubed root of 25.
Which irrational number is between cubed root of 9 and cubed root of 25
3 answers
why are you using square roots, when the question was about cube roots?
Since ∛9 ≈ 2.08 and ∛25 ≈ 2.92, there are infinitely many irrational numbers between ∛9 and ∛25.
Since ∛9 ≈ 2.08 and ∛25 ≈ 2.92, there are infinitely many irrational numbers between ∛9 and ∛25.
You are correct, my apologies for the confusion. Since the question is about cube roots, we can say that there are infinitely many irrational numbers between ∛9 and ∛25. This is because the set of irrational numbers is dense in the real number line, which means that between any two real numbers, there are infinitely many irrational numbers. So, we can conclude that there are infinitely many irrational numbers between ∛9 and ∛25, and we do not need to use square roots for this problem. Thank you for bringing this to my attention.