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Which events are NOT independent?
Landing on heads after tossing a coin and rolling a 3 on a 6- sided number cube
Choosing a marble from a jar and landing on tails after tossing a coin
Choosing a 5 from a deck of cards replacing it and then choosing an ace as the second card
Choosing a card at random from a deck without replacing it and choosing another card at random
If a coin is tossed and a number cube is rolled what is the probability that the coin shows heads and the number cube shows 3?
1/2
1/9
1/6
1/12
The probability of winning a game is 25%. How many times should you expect to win if you play 36 times?
A. 3 times
B. 7 times
C. 9 times
D. 11 times
A survey showed that 56% of car owners prefer four – door cars, 31% prefer two – door cars, and 13% have no preference. You ask 300 people. How many do you think will prefer four-door cars?
A. 218 people
B. 168 people
C. 233 people
D. 68 people
Tony works in a factory that produces 1,000 computers each day. When 50 computers were sampled, it was found that 7 were defective. Estimate how many defective computers are made each day.
A. 140 computers
B. 7 computers
C. 169 computers
D. 265 computers
An ice cream shop offers 5 different flavors of ice cream and 9 different toppings. How many choices are possible for a single serving of ice cream with one topping?
14 choices
45 choices
52 choices
63 choices
23 answers
okay sorry write teacher
okay this is what I thought
1. A
2. B
3.B
4.D
5. A
6.C
okay this is what I thought
1. A
2. B
3.B
4.D
5. A
6.C
you have 2, 5, 6 right
It would help if you numbered your questions.
1. your last choice is dependent , thus NOT independent
D
2. prob(heads and 3) = (1/2)(1/6) = 1/12
D
3. prob = 1/4, so of 36 cases, we can expect 9
C
4. prob(4door) = .56, so of 300 asked we expect 168
B
5. Prob(defective) = 7/50
number defective in 1000 = (7/50)(1000) = 140
A , YEAHH, you guessed one right!!
6. number of cones = (5)(9) = 45
B
These are very basic and elementary question in probability, I think you are just guessing
1. your last choice is dependent , thus NOT independent
D
2. prob(heads and 3) = (1/2)(1/6) = 1/12
D
3. prob = 1/4, so of 36 cases, we can expect 9
C
4. prob(4door) = .56, so of 300 asked we expect 168
B
5. Prob(defective) = 7/50
number defective in 1000 = (7/50)(1000) = 140
A , YEAHH, you guessed one right!!
6. number of cones = (5)(9) = 45
B
These are very basic and elementary question in probability, I think you are just guessing
i need help on the test please now........someone
c
a
b
b
a
b
c
a
a
b
c
d
c
d
a
b
b
a
b
c
a
a
b
c
d
c
d
asalam salam
His answers are wrong plz listen to me
Asalam u Alaikum warahamatulahi wabarakatu
It's what u say after someone says Asalam U Alaikum
It's what u say after someone says Asalam U Alaikum
HE cORRECT!!!! i GOT 14/14 last qestios is an easy people like u just dont want u to get the awnsers
Is this the exploring probability unit test for connexus
I really need help with this test.
Pleaseeeee help im not tying to cheat im struggling so bad my mom put me in this crappy school :(
I hate online school brub
Bot i need help
Of course, I would be happy to help. What are your questions?
Which event are not independent?
A. Landing on heads after tossing a coin and rolling a 3 on a 6 sided nuber cube.
B. Choosing a marble from a jar and landing on tails after tossing a coin.
C. Choosing a 5 from a deck of cards, replacing it, and then choosing an ace as the second card.
D. Choosing a card at random from a deck, without replacing it, and choosing another card at random.
A. Landing on heads after tossing a coin and rolling a 3 on a 6 sided nuber cube.
B. Choosing a marble from a jar and landing on tails after tossing a coin.
C. Choosing a 5 from a deck of cards, replacing it, and then choosing an ace as the second card.
D. Choosing a card at random from a deck, without replacing it, and choosing another card at random.
Bot help me with that
The event that is not independent is option C: choosing a 5 from a deck of cards, replacing it, and then choosing an ace as the second card.
This is because the probability of choosing an ace as the second card is affected by the fact that a 5 was previously chosen and replaced in the deck.
This is because the probability of choosing an ace as the second card is affected by the fact that a 5 was previously chosen and replaced in the deck.
Bot help me on. Sammy like to mix and match her necklace, 2 braclets, and 3 hats. The colors are listed in the table. On Monday, she randomly picks a bracelet, a necklace, and a hat. What is the possibility of Sammy choosing a red necklace and yellow bracelet? Necklace:Red, Green, Gold Silver. Bracelet: Red Yellow
The total number of possible outcomes is the product of the number of options for each accessory:
Total possible outcomes = 3 necklaces * 2 bracelets * 3 hats = 18
The desired outcome is Sammy choosing a red necklace and a yellow bracelet. According to the table, the probability of each of these individual events occurring is:
Probability of choosing a red necklace = 1/4
Probability of choosing a yellow bracelet = 1/2
The probability of both of these events happening together is the product of the individual probabilities:
Probability of choosing a red necklace and yellow bracelet = (1/4) * (1/2) = 1/8
So, the probability of Sammy choosing a red necklace and a yellow bracelet is 1/8 or 0.125.
Total possible outcomes = 3 necklaces * 2 bracelets * 3 hats = 18
The desired outcome is Sammy choosing a red necklace and a yellow bracelet. According to the table, the probability of each of these individual events occurring is:
Probability of choosing a red necklace = 1/4
Probability of choosing a yellow bracelet = 1/2
The probability of both of these events happening together is the product of the individual probabilities:
Probability of choosing a red necklace and yellow bracelet = (1/4) * (1/2) = 1/8
So, the probability of Sammy choosing a red necklace and a yellow bracelet is 1/8 or 0.125.
Thank you very much bot
You're welcome! If you have any other questions, please feel free to ask!
0 answers