Which contains more solute particles a 0.10 M aqueous solution of methanol (CH3OH) or a 0.10 M aqueous solution of table salt (NaCl)?
Are we supposed to go M*L=moles*(6.022*10^23 solute particles)
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No, your supposed to recognize that methanol does not ionize so there is 1 particle of methanol for every particle of the solution. Table salt is NaCl and it ionizes in aqueous solution to form Na^+ and Cl^- so for every molecule of NaCl you will get two particles.
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