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The density of acetonitrile, CH3CN, is 0.786 g/mL, and the density of methanol, CH3OH, is 0.791 g/mL. A solution is made by dis...Asked by مرح محمود شحادة احمد
The density of acetonitrile, CH3CN, is 0.786 g/mL, and the density of methanol, CH3OH, is 0.791 g/mL.
A solution is made by dissolving 15.0 g of methanol in 250.0 mL of acetonitrile. Assuming that the
volumes of the solute and solvent are additive, what is the molarity of methanol in the solution?
A solution is made by dissolving 15.0 g of methanol in 250.0 mL of acetonitrile. Assuming that the
volumes of the solute and solvent are additive, what is the molarity of methanol in the solution?
Answers
Answered by
DrBob222
mass = volume x density or
v = m/d
v methanol = 15.0 g/0.791 g/mL = 19.0 rounded.
v acetonitrile = 250 mL.
Total volume = 269 mL
moles CH3OH = grams/molar mass = 15.0/32 = 0.469 rounded
molarity = M = moles/L solution = 0.469/0.269 = ?
Check my arithmetic.
v = m/d
v methanol = 15.0 g/0.791 g/mL = 19.0 rounded.
v acetonitrile = 250 mL.
Total volume = 269 mL
moles CH3OH = grams/molar mass = 15.0/32 = 0.469 rounded
molarity = M = moles/L solution = 0.469/0.269 = ?
Check my arithmetic.