Whether or not the reaction above can occur and result in an actual chemical change, we can write and balance an equation. Use the drop downs to add the correct coefficients to balance the equation. (4 points) Fe(OH)2 + Mn → Mn(OH)4 + Fe

Answer 1

To balance the chemical equation:

Given Reaction: \[ \text{Fe(OH)}_2 + \text{Mn} \rightarrow \text{Mn(OH)}_4 + \text{Fe} \]

Balancing Steps:

1. Write down the number of atoms of each element on both sides of the equation.

On the left side:

• Fe: 1
• O: 2
• H: 2
• Mn: 1

On the right side:

• Fe: 1
• O: 4
• H: 4
• Mn: 1

2. Balance the oxygen (O) atoms:
   • We have 2 O on the left and 4 O on the right. To balance this, we can put a coefficient of 2 in front of Fe(OH)₂ on the left: \[ 2\text{Fe(OH)}_2 + \text{Mn} \rightarrow \text{Mn(OH)}_4 + \text{Fe} \]

Now we have:

• Fe: 2 (left)
• O: 4 (left)
• H: 4 (left)
• Mn: 1 (left)

On the right side:

• Fe: 1 (not balanced)
• O: 4 (right)
• H: 4 (right)
• Mn: 1 (right)

3. Balance the Iron (Fe):
   • We need to balance the Fe atoms. To do this, we can place a coefficient of 2 in front of Fe on the right side: \[ 2\text{Fe(OH)}_2 + \text{Mn} \rightarrow \text{Mn(OH)}_4 + 2\text{Fe} \]

Now we have:

• Fe: 2 (both sides)
• O: 4 (both sides)
• H: 4 (both sides)
• Mn: 1 (both sides)

4. Final Balanced Equation: \[ 2\text{Fe(OH)}_2 + \text{Mn} \rightarrow \text{Mn(OH)}_4 + 2\text{Fe} \]

Coefficients:

• For Fe(OH)₂: 2
• For Mn: 1
• For Mn(OH)₄: 1
• For Fe: 2

So, the final balanced equation is: \[ 2\text{Fe(OH)}_2 + 1\text{Mn} \rightarrow 1\text{Mn(OH)}_4 + 2\text{Fe} \]