Whether or not the reaction above can occur and result in an actual chemical change, we can write and balance an equation. Use the drop downs to add the correct coefficients to balance the equation. (4 points) hgCl2 + Al → AlCl3 + Hg

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To balance the equation for the reaction between mercuric chloride (HgCl₂) and aluminum (Al) resulting in aluminum chloride (AlCl₃) and mercury (Hg), we need to ensure that the number of each type of atom is the same on both sides of the equation.

The unbalanced equation is as follows: \[ \text{HgCl}_2 + \text{Al} \rightarrow \text{AlCl}_3 + \text{Hg} \]

Balancing the Equation:

  1. Starting with the reactants:

    • We have 2 chlorine atoms (from HgCl₂) and 1 aluminum atom.
  2. On the product side:

    • AlCl₃ has 3 chlorine atoms and 1 aluminum atom, and there's also 1 mercury atom.

Balancing Steps:

  • We first need to balance the chlorine atoms. Since there are 2 Cl in HgCl₂, we will need to adjust coefficients:
  • We know that for every 1 HgCl₂, we require 1 Al, but since AlCl₃ requires 3 Cl, we need 3 times the number of HgCl₂.

So let's add coefficients in front of each compound. To balance chlorine, we need \( 3 \) AlCl₃, which means we need \( 3 \) HgCl₂:

\[ 3 \text{HgCl}_2 + 2 \text{Al} \rightarrow 2 \text{AlCl}_3 + 3 \text{Hg} \]

Final Balanced Equation:

  • This leads to the balanced equation: \[ 3 \text{HgCl}_2 + 2 \text{Al} \rightarrow 2 \text{AlCl}_3 + 3 \text{Hg} \]

Coefficients:

  • Coefficient in front of HgCl₂: 3
  • Coefficient in front of Al: 2
  • Coefficient in front of AlCl₃: 2
  • Coefficient in front of Hg: 3

So the final balanced equation is: \[ 3 \text{HgCl}_2 + 2 \text{Al} \rightarrow 2 \text{AlCl}_3 + 3 \text{Hg} \]