To graph the equations y = 2x + 4 and -2x + y = 8, we need to rewrite the second equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
First, we rewrite the second equation as y = 2x + 8 by moving the -2x term to the other side of the equation:
-2x + y = 8
y = 2x + 8
Now we have both equations in slope-intercept form:
y = 2x + 4
y = 2x + 8
Both equations have the same slope of 2, which means they are parallel lines. However, they have different y-intercepts at (0,4) and (0,8) respectively.
On the graph:
- The line y = 2x + 4 will pass through the point (0,4) and have a positive slope.
- The line y = 2x + 8 will pass through the point (0,8) and also have a positive slope.
Therefore, the lines will be parallel to each other, with one line passing through the point (0,4) and the other passing through the point (0,8).
where would y = 2x + 4 and -2x + y = 8 go on the graph?
1 answer