To find where the line crosses the y-axis, we need to set x = 0 and solve for y.
Given the equation: 6x - 2y = -10
Setting x = 0, we get:
6(0) - 2y = -10
-2y = -10
y = -10 / -2
y = 5
Therefore, the line 6x - 2y = -10 crosses the y-axis at the point (0, 5).
where does the line 6x - 2y = -10 cross the y-axis?
1 answer