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tangent line and normal line of y=(sqrtx)/(x+1) when p=(4,2/5)
14 years ago

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p=(x1, y1)

tangent line:
y-y1=m(x-x1)

normal line:
y-y1=(-1/m)(x-x1)

where m=slope=y'

http://www.cliffsnotes.com/study_guide/Tangent-and-Normal-Lines.topicArticleId-39909,articleId-39887.html
14 years ago

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