Asked by courtney
tangent line and normal line of y=(sqrtx)/(x+1) when p=(4,2/5)
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Answered by
TutorCat
p=(x1, y1)
tangent line:
y-y1=m(x-x1)
normal line:
y-y1=(-1/m)(x-x1)
where m=slope=y'
http://www.cliffsnotes.com/study_guide/Tangent-and-Normal-Lines.topicArticleId-39909,articleId-39887.html
tangent line:
y-y1=m(x-x1)
normal line:
y-y1=(-1/m)(x-x1)
where m=slope=y'
http://www.cliffsnotes.com/study_guide/Tangent-and-Normal-Lines.topicArticleId-39909,articleId-39887.html
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