When you take your 1300-kg car out for a spin, you go around a corner of radius 57.8 m with a speed of 15.2 m/s. The coefficient of static friction between the car and the road is 0.82. Assuming your car doesn't skid, what is the force exerted on it by static friction?

Question

Please show work, thank you!

Answer 1

That would equal the centripetal force,
M V^2/R,
if the car does not skid. It will not depend upon the static friction coefficient