figure the moles of sodium you used.
then
MolesNa/2 liberated 5890J
Hr= -5890J*2/molesYouUsed
When you add 0.567 g of sodium metal to an excess of hydrochloric acid, you find that 5890 J of heat are produced. What is the enthalpy of the reaction as written below?
2Na(s)+2HCl(aq)=2NaCl(aq)+H2(g)
4 answers
5890 J x (2*23/0.567) = ?
477848.3?
That's ok but you have too many significant figures in the answer.