When you add 0.567 g of sodium metal to an excess of hydrochloric acid, you find that 5890 J of heat are produced. What is the enthalpy of the reaction as written below?

Question

2Na(s)+2HCl(aq)=2NaCl(aq)+H2(g)

Answer 1

figure the moles of sodium you used.

then
MolesNa/2 liberated 5890J

Hr= -5890J*2/molesYouUsed

Answer 2

5890 J x (2*23/0.567) = ?

Answer 3

477848.3?

Answer 4

That's ok but you have too many significant figures in the answer.