When you add 0.320 g of sodium metal to an excess of hydrochloric acid, you find that 3330 J of heat are produced. What is the enthalpy of the reaction as written below?

2Na(s) + 2HCl(aq) --> 2NaCl(aq) +H2(g

1 answer

As written? As written, is says the heat of reaction is 3330J per .320g Na.

lets do a proportion.

2molesNa/.320g=Hr/3330J

change 2 moles Na to grms, solve for Heat of Reaction.