Asked by Catherine
When you add 0.320 g of sodium metal to an excess of hydrochloric acid, you find that 3330 J of heat are produced. What is the enthalpy of the reaction as written below?
2Na(s) + 2HCl(aq) --> 2NaCl(aq) +H2(g
2Na(s) + 2HCl(aq) --> 2NaCl(aq) +H2(g
Answers
Answered by
bobpursley
As written? As written, is says the heat of reaction is 3330J per .320g Na.
lets do a proportion.
2molesNa/.320g=Hr/3330J
change 2 moles Na to grms, solve for Heat of Reaction.
lets do a proportion.
2molesNa/.320g=Hr/3330J
change 2 moles Na to grms, solve for Heat of Reaction.
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