When working with the properties of Saturated Steam.

The pressure table supplied states:

Pressure kPa = 1100 (P)
Temp in Celsius = 184.09 (T)
Specific Volume = Sat. Liquid = 1.1330 (Vf)
Specific Volume = Sat.Vapor = 177.53 (Vg)
Enthalpy = Saturated Liquid = 781.34 (Hf)
Enthalpy = Evap = 2000.4 (Hfg)
Enthalpy = Saturated Vapor = 2781.7 (Hg)

Now using the information supplied:
Calculate the volume of 12kg of water at a pressure of 1100kPa, the answer is 0.014m^3.

I need help finding which formula is used to find the answer. Thank you.