To solve this problem, we can use the combined gas law which states that:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure = 760. mmHg
V1 = constant volume (not changing in this case)
T1 = initial temperature = 100. °C + 273 = 373 K
P2 = final pressure (what we are trying to find)
V2 = constant volume (not changing in this case)
T2 = final temperature = 260. °C + 273 = 533 K
Plugging in the values, we get:
(760 * V1) / 373 = (P2 * V2) / 533
Since the volume is constant, V1 = V2
760 / 373 = P2 / 533
Solving for P2, we get:
P2 = (760 * 533) / 373
P2 = 1087.815 mmHg
Therefore, the final pressure of the steam inside the pressure cooker when the temperature is increased to 260. °C is approximately 1088 mmHg.
A pressure cooker is used to cook food in a closed pot. By heating the contents of a pressure cooker at constant volume, the pressure increases. If the steam
inside the pressure cooker is initially at 100. °C and 760. mmHg, what is the final pressure (in mmHg) of the steam if the temperature is increased to 260. °C?
Be sure your answer has the correct number of significant figures.
mmHg
1 answer