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When the three medians of the triangle are drawn, they meet at a single point. What is the point of the centroid? Leave all res...Asked by Stephen
When the three medians of the triangle are drawn, they meet at a single point. What is the point of the centroid? Leave all results in fractions. (1 point) centroid= (,) (2,3),(-3,-1) (2,-1)
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Answered by
GPT-4o mini
To find the centroid of a triangle given its vertices, we use the formula for the centroid \((G)\) which is the average of the coordinates of the vertices. The formula is:
\[
G\left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)
\]
Given the vertices of the triangle are \((2, 3)\), \((-3, -1)\), and \((2, -1)\), we can plug in these coordinates into the formula.
1. \(x_1 = 2\), \(y_1 = 3\)
2. \(x_2 = -3\), \(y_2 = -1\)
3. \(x_3 = 2\), \(y_3 = -1\)
Now calculate the coordinates of the centroid:
\[
G_x = \frac{2 + (-3) + 2}{3} = \frac{2 - 3 + 2}{3} = \frac{1}{3}
\]
\[
G_y = \frac{3 + (-1) + (-1)}{3} = \frac{3 - 1 - 1}{3} = \frac{1}{3}
\]
Thus, the centroid of the triangle is:
\[
\text{centroid} = \left( \frac{1}{3}, \frac{1}{3} \right)
\]
So, the final answer is:
\[
\text{centroid} = \left( \frac{1}{3}, \frac{1}{3} \right)
\]
\[
G\left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)
\]
Given the vertices of the triangle are \((2, 3)\), \((-3, -1)\), and \((2, -1)\), we can plug in these coordinates into the formula.
1. \(x_1 = 2\), \(y_1 = 3\)
2. \(x_2 = -3\), \(y_2 = -1\)
3. \(x_3 = 2\), \(y_3 = -1\)
Now calculate the coordinates of the centroid:
\[
G_x = \frac{2 + (-3) + 2}{3} = \frac{2 - 3 + 2}{3} = \frac{1}{3}
\]
\[
G_y = \frac{3 + (-1) + (-1)}{3} = \frac{3 - 1 - 1}{3} = \frac{1}{3}
\]
Thus, the centroid of the triangle is:
\[
\text{centroid} = \left( \frac{1}{3}, \frac{1}{3} \right)
\]
So, the final answer is:
\[
\text{centroid} = \left( \frac{1}{3}, \frac{1}{3} \right)
\]
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