To find the probability that Nabhitha's score will be higher than 115, we need to calculate the probability of getting a score greater than 115 in a normal distribution with mean 115 and standard deviation 11.
To do this, we first need to calculate the z-score for a score of 115 in this distribution:
z = (x - mean) / standard deviation
z = (115 - 115) / 11
z = 0
Next, we need to find the area to the right of this z-score in the standard normal distribution table. Since the z-score is 0, the area to the right is 0.5000.
So, the probability that Nabhitha's score will be higher than 115 is 0.5.
When Nabhitha goes bowling, her scores are normally distributed with a mean of 115 and a standard deviation of 11. What is the probability that the next game Nabhitha bowls, her score will be higher than 115, to the nearest thousandth?
1 answer
1 answer