Asked by Kelly17

A 5.1 kg bowling ball and a 7.1 kg bowling ball rest on a rack 1.07 m apart.

(a) What is the force of gravity exerted on each of the balls by the other ball?

(b) At what separation is the force of gravity between the balls equal to 2.0 10-9 N?

Answers

Answered by Kelly17
part b says 2.0 E-9
Answered by Damon
F = G M1 M2 / d^2
= 6.67 * 10^-11 * 5.1 * 7.1 / 1.07^2
Answered by Damon
part b
2*10^-9 = 6.67*10^-11*5.1*7.1/d^2
solve for d
Answered by pascual
find the force of gravity between two 7.26kg bowling balls separated by 3m
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