Asked by Idali
A (10.25) kg bowling ball is hung on a (11.50) m long rope. It is then pulled back until the rope makes an angle of (39.0)o with the vertical and released. Find the tension in the rope when the ball is at the lowest point. Give your answer in N and with 3 significant figures.
Answers
Answered by
bobpursley
The height h thru which it will fall is
H=11.50(1-cos39)
1/2mv^2=mgh
v=sqrt(2gh)
exclamations points are to me a bit exaggerated.
H=11.50(1-cos39)
1/2mv^2=mgh
v=sqrt(2gh)
exclamations points are to me a bit exaggerated.
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