1. Write the balanced equation.
2. Convert 59.0 L CO2 at STP to moles. moles = 59.0 L x (1 mole/22.4 L) = ??
3. Using the coefficients in the balanced equation, convert moles CO2 to moles CaCO3.
4. Convert moles CaCO3 to grams.
grams = moles x molar mass.
When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction
CaCO3(s)---->CaO(s)+CO2(g)
How many grams of calcium carbonate are needed to produce 59.0L of carbon dioxide at STP?
2 answers
mb.b.
2 answers