balance the equation
CaCO3>> CaO + CO2
so for every mole of CO2, you need one mole of calcium carbonate.
How many moles of CO2 is 49grams?
When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction
How many grams of calcium carbonate are needed to produce 49.0 of carbon dioxide at STP?
2 answers
111.3636gm of CaCo3