When displaced from equilibrium by a small amount, the two hydrogen atoms in an \rm H_{2} molecule are acted on by a restoring force F_{x}=-k_1 x with k_1 = 510 N/m.
Calculate the oscillation frequency f of the H2 molecule. Use m_eff = m/2 as the "effective mass" of the system, where m in the mass of a hydrogen atom.
Take the mass of a hydrogen atom as 1.008 u,
where 1 u=1.661 times 10^-27 kg. Express your answer in hertz.
f=___Hz
1 answer
f = (k_1/m_eff)^(1/2) = (510 N/m)/(1.008 u/2)^(1/2) = 3.945 x 10^14 Hz
1 answer