What is the significance of a very large Kp value on the equilibrium concentration of H2 in the reaction: 2H2(g) + O2(g) ->2H2O(g)?

Question

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There is very little H2 at equilibrium.

The amount of H2 is always equal to the amount of O2 at equilibrium.

The amount of H2 does not depend on the value of Kp.

There is a significant amount of H2 at equilibrium.

Answer 1

So Kp = p(H2O)^2/p(H2)^2*p(O2)
A large Kp means high p for H2O and low p for H2 and O2. If you have low p for H2 there isn't much there.

Answer 2

Oh Robert, you amaze me with your words

Answer 3

There is very little H2 at equilibrium.