convert to moles and see which reagent gets used up:
32g CaCO3 = 32/100 = 0.32 moles
11g HCl = 11/36.46 = 0.30 moles
From the equation, each mole CaCO3 requires 2 moles HCl. So, only 0.15 moles of CaCO3 will be used, producing 0.15 moles CaCl2
.15 moles CaCl2 = .15*110.98 = 1.65g CaCl2
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
CaCO3(s)+2HCl(aq)--> CaCl2(aq)+H2O (l)+CO2(g)
How many grams of calcium chloride will be produced when 32.0 g of calcium carbonate are combined with 11.0 g of hydrochloric acid?
3 answers
Oops 16.65g
Where did you get .15 moles of CaCl2 from?
1 answer