mols CaCO3 = grams/molar mass = ?
mols HCl = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CaCO3 to mols CaCl2.
Do the same to convert mols HCl to mols CaCl2.
It is likely that the two values will not agree which means one of them is not right. The correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Now convert the smaller value of mols CaCl2 to grams. grams CaCl2 = mols CaCl2 x molar mass CaCl2.
For the excess reagent.
LR = limiting reagent
OR = other reagent; i.e., the non-limiting reagent.
In a process similar to converting mols HCl and CaCO3 to mols CaCl2, convert mols LR to mols of the OR. That will give you mols the OR used by the LR. Then mols OR initially - mols OR used = mols OR left after the reaction is complete.
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
CaCO3(s)+2HCl(aq)=CaCl2(aq)+H2O(l)+CO2(g)
How many grams of calcium chloride will be produced when 27.0 g of calcium carbonate are combined with 11.0 g of hydrochloric acid?
Which reactant is in excess and how many grams of this reactant will remain after the reaction is complete?
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