5 and 6 are factors, but 7 is not.
Explore multiples of 30.
when asked how many pennies she had a collector said If I arrange them in stacks of five, none are leftover if I arrange them in stacks of six, none are leftover if I arrange them in stacks of seven one is left over. What is the least number of coins she could have
2 answers
she has 30 coins it can be divide by 5 and 6 and 7 but two will be left over
the least number of coins she could have would be 28
since it only two number away from 30
the least number of coins she could have would be 28
since it only two number away from 30
1 answer