8(12) + 7

A 11 piles of 10 pennies with 7 leftover pennies
B A rectangular array of pennies that is 9 pennies long and 12 pennies wide with 5 leftover pennies
C 8 stacks of 12 pennies with 7 leftover pennies
D A rectangular array of pennies that is 6 pennies wide and 20 pennies long with 5 leftover pennies

1 answer

To solve the expression \(8(12) + 7\), we first calculate \(8(12)\):

\[ 8(12) = 96 \]

Then we add \(7\):

\[ 96 + 7 = 103 \]

Now let's interpret the result of \(103\) in terms of the options given:

  • Option A: 11 piles of 10 pennies with 7 leftover pennies adds up to \(11 \times 10 + 7 = 110 + 7 = 117\).
  • Option B: A rectangular array of 9 pennies long and 12 pennies wide with 5 leftover pennies would be \(9 \times 12 + 5 = 108 + 5 = 113\).
  • Option C: 8 stacks of 12 pennies with 7 leftover pennies counts as \(8 \times 12 + 7 = 96 + 7 = 103\).
  • Option D: A rectangular array of 6 pennies wide and 20 pennies long with 5 leftover pennies gives us \(6 \times 20 + 5 = 120 + 5 = 125\).

Thus, the correct answer that matches the calculation \(8(12) + 7 = 103\) is:

C. 8 stacks of 12 pennies with 7 leftover pennies.