You know that the average velocity is
[y(3+h)-y(3)]/h
So, just plug in the numbers and grind out the answers.
When a ball is thrown vertically upward
into the air with a velocity of 79 ft/sec its
height, y(t), in feet after t seconds is given by
y(t) = 79t − 16t
2
.
Find the average velocity of the ball over
the interval from 3 to 3 + h seconds, h 6=/= 0.
1. average vel. = −(17 − 16h) ft/sec
2. average vel. = −(17 + 16h) ft/sec
3. average vel. = −(21 + 16h) ft/sec
4. average vel. = −(21 − 16h) ft/sec
5. average vel. = −(17 − h) ft/sec
6. average vel. = −(21 + h) ft/sec
1 answer