from the mass (remember mg is weight), find the spring constant.
Work=1/2 kx^2
When a 4.48 kg mass is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.68 cm.
How much work must an external agent do to stretch the spring 3.96 cm from its unstretched position?
2 answers
128.45
1 answer