Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
When a 2.60-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.30 cm. (a)...Asked by Anonymous
When a 2.50-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 3.13 cm.
a)What is the force constant of the spring?
b) If the 2.50-kg object is removed, how far will the spring stretch if a 1.25-kg block is hung on it?
a)What is the force constant of the spring?
b) If the 2.50-kg object is removed, how far will the spring stretch if a 1.25-kg block is hung on it?
Answers
Answered by
bobpursley
k= force/x= mg/.0313
b) x= force/k=mg/k it better be half as far.
b) x= force/k=mg/k it better be half as far.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.