millimols HCl = 50.00 x 1.00M = ?
mmols NaOH = 49.99 x 1.00 M = ?
Subtract to obtain mmols H^+ left, mmols H^+/(50.00+49.99) and convert to pH.
Do the same for 50.00 and 50.01, subtract to find excess OH^- mmols, then
OH^- = mmols OH/total mL and convert to pOH and pH.
When 50.0ml of 1.00M HCl is titrated with 1.00M NaOH, the pH increases. calculate the difference in pH of the system when you add 49.99ml NaOH and 50.01ml of NaOH. Please work out detailed steps.
2 answers
No