50.0 mL of 0.116 M NaOH is titrated with 0.0750 M HCl. Calculate the pH after the addition of 5.0 mL volume of acid.

Answer 1

mols NaOH initially = M x L = ?
mols HCl added = M x L = ?
mols NaOH remaining = mols NaOH - mols HCl.
Then (OH^-) = (NaOH) and
pOH = -log(OH^-)
Then pH + pOH = pKw = 14. You know pKw and pOH solve for pH.