When 112 g of water at a temperature of 22.5°C is mixed with 65.1 g of water at an unknown temperature, the final temperature of the resulting mixture is 46.3°C. What was the initial temperature of the second sample of water?

Answer 1

loss heat hot water + gain of heat by cold water = 0

[Mass1H2O x specific heat x (Tfinal-Tinitial)] + [mass2H2O x specific heat x (Tfinal-Tinitial)] = 0